These are the solutions to the .
Here’s one way to use random sampling to determine the ratio of evens to odds:
| | import random |
| | |
| | array = [] |
| | number_of_integers = 1000001 |
| | |
| | |
| | for i in range(number_of_integers): |
| | array.append(i) |
| | |
| | random.shuffle(array) |
| | |
| | number_of_evens = 0 |
| | number_of_odds = 0 |
| | |
| | random_sample_size = 500 |
| | |
| | for _ in range(random_sample_size): |
| | random_index = random.randint(0, number_of_integers - 1) |
| | if array[random_index] % 2 == 0: |
| | number_of_evens += 1 |
| | else: |
| | number_of_odds += 1 |
| | |
| | percentage_of_evens = (number_of_evens / random_sample_size) * 100 |
| | percentage_of_odds = (number_of_odds / random_sample_size) * 100 |
| | |
| | print([percentage_of_evens, percentage_of_odds]) |
If The Formula—even once—produces a result that isn’t 1, then we know for certain that N is composite.
Each time I run The Formula on a prime number, there’s no more than a 50 percent chance that I’ll get a result of 1. Therefore, each time I run the formula it’s akin to flipping a coin. Getting a 1 four times is like a coin landing on heads four times. The odds of this are:
| | 1/2 * 1/2 * 1/2 * 1/2 = 1/16 |
That is, there’s a 1/16 chance that N in this case is prime.